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655523343325483 is a prime number
BaseRepresentation
bin1001010100001100011110110…
…0000001010101100100101011
310011222000102022212222002010021
42111003013230001111210223
51141410043301342403413
610242103133330101311
7255034666353430453
oct22503075401254453
93158012285862107
10655523343325483
1117a962985937a16
126163099541a837
13221a078068ac49
14b7c36db780d63
1550bb9ee6ad18d
hex25431ec05592b

655523343325483 has 2 divisors, whose sum is σ = 655523343325484. Its totient is φ = 655523343325482.

The previous prime is 655523343325481. The next prime is 655523343325579. The reversal of 655523343325483 is 384523343325556.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 655523343325483 - 21 = 655523343325481 is a prime.

It is a super-3 number, since 3×6555233433254833 (a number of 45 digits) contains 333 as substring.

Together with 655523343325481, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (655523343325481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327761671662741 + 327761671662742.

It is an arithmetic number, because the mean of its divisors is an integer number (327761671662742).

Almost surely, 2655523343325483 is an apocalyptic number.

655523343325483 is a deficient number, since it is larger than the sum of its proper divisors (1).

655523343325483 is an equidigital number, since it uses as much as digits as its factorization.

655523343325483 is an evil number, because the sum of its binary digits is even.

The product of its digits is 466560000, while the sum is 61.

The spelling of 655523343325483 in words is "six hundred fifty-five trillion, five hundred twenty-three billion, three hundred forty-three million, three hundred twenty-five thousand, four hundred eighty-three".