Base | Representation |
---|---|
bin | 11101110111101010001110… |
… | …10010000000011100100011 |
3 | 22121120100020000020010222121 |
4 | 32323311013102000130203 |
5 | 32102132044433313413 |
6 | 351410512331245111 |
7 | 16556343664262644 |
oct | 1673650722003443 |
9 | 277510200203877 |
10 | 65684130760483 |
11 | 19a24535483784 |
12 | 744a0365a9797 |
13 | 2a85caa44a121 |
14 | 12311b396d6cb |
15 | 78d8dd0b4b8d |
hex | 3bbd47480723 |
65684130760483 has 2 divisors, whose sum is σ = 65684130760484. Its totient is φ = 65684130760482.
The previous prime is 65684130760477. The next prime is 65684130760519. The reversal of 65684130760483 is 38406703148656.
65684130760483 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 65684130760483 - 213 = 65684130752291 is a prime.
It is not a weakly prime, because it can be changed into another prime (65684130766483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32842065380241 + 32842065380242.
It is an arithmetic number, because the mean of its divisors is an integer number (32842065380242).
Almost surely, 265684130760483 is an apocalyptic number.
65684130760483 is a deficient number, since it is larger than the sum of its proper divisors (1).
65684130760483 is an equidigital number, since it uses as much as digits as its factorization.
65684130760483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69672960, while the sum is 61.
The spelling of 65684130760483 in words is "sixty-five trillion, six hundred eighty-four billion, one hundred thirty million, seven hundred sixty thousand, four hundred eighty-three".
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