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65925131533 is a prime number
BaseRepresentation
bin111101011001011100…
…011010110100001101
320022011102202200012021
4331121130122310031
52040003313202113
650141404210141
74522454241442
oct753134326415
9208142680167
1065925131533
1125a60022088
121093a239951
1362a8171491
1432957739c9
151aac9ec48d
hexf5971ad0d

65925131533 has 2 divisors, whose sum is σ = 65925131534. Its totient is φ = 65925131532.

The previous prime is 65925131491. The next prime is 65925131539. The reversal of 65925131533 is 33513152956.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59620453929 + 6304677604 = 244173^2 + 79402^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-65925131533 is a prime.

It is a super-2 number, since 2×659251315332 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 65925131533.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (65925131539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32962565766 + 32962565767.

It is an arithmetic number, because the mean of its divisors is an integer number (32962565767).

Almost surely, 265925131533 is an apocalyptic number.

It is an amenable number.

65925131533 is a deficient number, since it is larger than the sum of its proper divisors (1).

65925131533 is an equidigital number, since it uses as much as digits as its factorization.

65925131533 is an evil number, because the sum of its binary digits is even.

The product of its digits is 364500, while the sum is 43.

The spelling of 65925131533 in words is "sixty-five billion, nine hundred twenty-five million, one hundred thirty-one thousand, five hundred thirty-three".