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65950494733 is a prime number
BaseRepresentation
bin111101011010111101…
…001011000000001101
320022020012111020222001
4331122331023000031
52040031311312413
650144111552301
74523212645564
oct753275130015
9208205436861
1065950494733
1125a73375902
121094682b691
1362b04b1aa6
143298c96bdb
151aaed5c4dd
hexf5af4b00d

65950494733 has 2 divisors, whose sum is σ = 65950494734. Its totient is φ = 65950494732.

The previous prime is 65950494719. The next prime is 65950494769. The reversal of 65950494733 is 33749405956.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36587273284 + 29363221449 = 191278^2 + 171357^2 .

It is a cyclic number.

It is not a de Polignac number, because 65950494733 - 233 = 57360560141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (65950494713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32975247366 + 32975247367.

It is an arithmetic number, because the mean of its divisors is an integer number (32975247367).

Almost surely, 265950494733 is an apocalyptic number.

It is an amenable number.

65950494733 is a deficient number, since it is larger than the sum of its proper divisors (1).

65950494733 is an equidigital number, since it uses as much as digits as its factorization.

65950494733 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12247200, while the sum is 55.

The spelling of 65950494733 in words is "sixty-five billion, nine hundred fifty million, four hundred ninety-four thousand, seven hundred thirty-three".