6601041365143 has 4 divisors (see below), whose sum is σ = 6606107399728. Its totient is φ = 6595975330560.

The previous prime is 6601041365129. The next prime is 6601041365153. The reversal of 6601041365143 is 3415631401066.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 6601041365143 - 2¹³ = 6601041356951 is a prime.

It is a super-2 number, since 2×6601041365143² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 6601041365096 and 6601041365105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6601041365153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2533015338 + ... + 2533017943.

It is an arithmetic number, because the mean of its divisors is an integer number (1651526849932).

Almost surely, 2^{6601041365143} is an apocalyptic number.

6601041365143 is a deficient number, since it is larger than the sum of its proper divisors (5066034585).

6601041365143 is a wasteful number, since it uses less digits than its factorization.

6601041365143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5066034584.

The product of its (nonzero) digits is 155520, while the sum is 40.

The spelling of 6601041365143 in words is "six trillion, six hundred one billion, forty-one million, three hundred sixty-five thousand, one hundred forty-three".