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66143011333 = 783214153173
BaseRepresentation
bin111101100110011011…
…100100001000000101
320022201121202010002111
4331212123210020011
52040430102330313
650215150141021
74531041214510
oct754633441005
9208647663074
1066143011333
1126062007433
121099b1b1771
136311348b39
1432b668bd77
151ac1bd943d
hexf666e4205

66143011333 has 16 divisors (see below), whose sum is σ = 76539931776. Its totient is φ = 55983735360.

The previous prime is 66143011331. The next prime is 66143011349. The reversal of 66143011333 is 33311034166.

It is not a de Polignac number, because 66143011333 - 21 = 66143011331 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 66143011295 and 66143011304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (66143011331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1217335 + ... + 1270507.

It is an arithmetic number, because the mean of its divisors is an integer number (4783745736).

Almost surely, 266143011333 is an apocalyptic number.

It is an amenable number.

66143011333 is a deficient number, since it is larger than the sum of its proper divisors (10396920443).

66143011333 is a wasteful number, since it uses less digits than its factorization.

66143011333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55404.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 66143011333 its reverse (33311034166), we get a palindrome (99454045499).

The spelling of 66143011333 in words is "sixty-six billion, one hundred forty-three million, eleven thousand, three hundred thirty-three".

Divisors: 1 7 83 581 2141 14987 53173 177703 372211 1243921 4413359 30893513 113843393 796903751 9449001619 66143011333