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6617349721153 is a prime number
BaseRepresentation
bin110000001001011100011…
…0001111000110001000001
3212102121112110221202112101
41200102320301320301001
51331404313012034103
622023545110030401
71252042044363463
oct140227061706101
925377473852471
106617349721153
112121447449276
128aa5a1048401
133900235999a2
1418c3d238a133
15b71ec05da1d
hex604b8c78c41

6617349721153 has 2 divisors, whose sum is σ = 6617349721154. Its totient is φ = 6617349721152.

The previous prime is 6617349721123. The next prime is 6617349721163. The reversal of 6617349721153 is 3511279437166.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6515603394624 + 101746326529 = 2552568^2 + 318977^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6617349721153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 6617349721094 and 6617349721103.

It is not a weakly prime, because it can be changed into another prime (6617349721123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3308674860576 + 3308674860577.

It is an arithmetic number, because the mean of its divisors is an integer number (3308674860577).

Almost surely, 26617349721153 is an apocalyptic number.

It is an amenable number.

6617349721153 is a deficient number, since it is larger than the sum of its proper divisors (1).

6617349721153 is an equidigital number, since it uses as much as digits as its factorization.

6617349721153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5715360, while the sum is 55.

The spelling of 6617349721153 in words is "six trillion, six hundred seventeen billion, three hundred forty-nine million, seven hundred twenty-one thousand, one hundred fifty-three".