Base | Representation |
---|---|
bin | 110000010000110100110… |
… | …1101101101111000111011 |
3 | 212111010110022212201000020 |
4 | 1200201221231231320323 |
5 | 1332134244443102042 |
6 | 22035130150541523 |
7 | 1253142646014534 |
oct | 140415155557073 |
9 | 25433408781006 |
10 | 6633203097147 |
11 | 2128142248300 |
12 | 8b16863678a3 |
13 | 39167bb66843 |
14 | 18d097a7168b |
15 | b7828c403ec |
hex | 60869b6de3b |
6633203097147 has 24 divisors (see below), whose sum is σ = 9721538856960. Its totient is φ = 4020060937200.
The previous prime is 6633203097127. The next prime is 6633203097173. The reversal of 6633203097147 is 7417903023366.
It is a de Polignac number, because none of the positive numbers 2k-6633203097147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6633203097147.
It is not an unprimeable number, because it can be changed into a prime (6633203097127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36307254 + ... + 36489492.
It is an arithmetic number, because the mean of its divisors is an integer number (405064119040).
Almost surely, 26633203097147 is an apocalyptic number.
6633203097147 is a deficient number, since it is larger than the sum of its proper divisors (3088335759813).
6633203097147 is a wasteful number, since it uses less digits than its factorization.
6633203097147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 282535 (or 282524 counting only the distinct ones).
The product of its (nonzero) digits is 3429216, while the sum is 51.
The spelling of 6633203097147 in words is "six trillion, six hundred thirty-three billion, two hundred three million, ninety-seven thousand, one hundred forty-seven".
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