Base | Representation |
---|---|
bin | 111101110111000100… |
… | …010000001100001011 |
3 | 20100110001220221122120 |
4 | 331313010100030023 |
5 | 2042013030104120 |
6 | 50303000222323 |
7 | 4541000434215 |
oct | 756704201413 |
9 | 210401827576 |
10 | 66422113035 |
11 | 261956076a3 |
12 | 10a5876a9a3 |
13 | 635710a685 |
14 | 33017815b5 |
15 | 1adb46b140 |
hex | f7711030b |
66422113035 has 16 divisors (see below), whose sum is σ = 106281485856. Its totient is φ = 35423091968.
The previous prime is 66422113027. The next prime is 66422113073. The reversal of 66422113035 is 53031122466.
It is a cyclic number.
It is not a de Polignac number, because 66422113035 - 23 = 66422113027 is a prime.
It is a super-2 number, since 2×664221130352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 66422112987 and 66422113005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 164167 + ... + 399743.
It is an arithmetic number, because the mean of its divisors is an integer number (6642592866).
Almost surely, 266422113035 is an apocalyptic number.
66422113035 is a deficient number, since it is larger than the sum of its proper divisors (39859372821).
66422113035 is a wasteful number, since it uses less digits than its factorization.
66422113035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 254382.
The product of its (nonzero) digits is 25920, while the sum is 33.
The spelling of 66422113035 in words is "sixty-six billion, four hundred twenty-two million, one hundred thirteen thousand, thirty-five".
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