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6681344143447 = 7391525262239
BaseRepresentation
bin110000100111001111100…
…1001001111000001010111
3212122201201100202020120001
41201032133021033001113
51333431343100042242
622113211144352131
71256465636114311
oct141163711170127
925581640666501
106681344143447
1121465a664a986
128baa80775647
1339608174485c
141915435407b1
15b8be52d3eb7
hex6139f24f057

6681344143447 has 4 divisors (see below), whose sum is σ = 6772869405760. Its totient is φ = 6589818881136.

The previous prime is 6681344143433. The next prime is 6681344143451. The reversal of 6681344143447 is 7443414431866.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 6681344143447 - 27 = 6681344143319 is a prime.

It is a super-3 number, since 3×66813441434473 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6681344143457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45762631047 + ... + 45762631192.

It is an arithmetic number, because the mean of its divisors is an integer number (1693217351440).

Almost surely, 26681344143447 is an apocalyptic number.

6681344143447 is a deficient number, since it is larger than the sum of its proper divisors (91525262313).

6681344143447 is an equidigital number, since it uses as much as digits as its factorization.

6681344143447 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91525262312.

The product of its digits is 18579456, while the sum is 55.

The spelling of 6681344143447 in words is "six trillion, six hundred eighty-one billion, three hundred forty-four million, one hundred forty-three thousand, four hundred forty-seven".

Divisors: 1 73 91525262239 6681344143447