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66854392701 = 322284797567
BaseRepresentation
bin111110010000110101…
…010001001101111101
320101120012100000212120
4332100311101031331
52043404211031301
650413521353153
74554466650615
oct762065211575
9211505300776
1066854392701
112639761a818
1210b594987b9
1363c5841765
143342d49a45
151b143a8e36
hexf90d5137d

66854392701 has 4 divisors (see below), whose sum is σ = 89139190272. Its totient is φ = 44569595132.

The previous prime is 66854392697. The next prime is 66854392733. The reversal of 66854392701 is 10729345866.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 66854392701 - 22 = 66854392697 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (66854392301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11142398781 + ... + 11142398786.

It is an arithmetic number, because the mean of its divisors is an integer number (22284797568).

It is a 1-persistent number, because it is pandigital, but 2⋅66854392701 = 133708785402 is not.

Almost surely, 266854392701 is an apocalyptic number.

It is an amenable number.

66854392701 is a deficient number, since it is larger than the sum of its proper divisors (22284797571).

66854392701 is a wasteful number, since it uses less digits than its factorization.

66854392701 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22284797570.

The product of its (nonzero) digits is 2177280, while the sum is 51.

The spelling of 66854392701 in words is "sixty-six billion, eight hundred fifty-four million, three hundred ninety-two thousand, seven hundred one".

Divisors: 1 3 22284797567 66854392701