Base | Representation |
---|---|
bin | 111110011111100011… |
… | …111101100110000001 |
3 | 20102012102100002201110 |
4 | 332133203331212001 |
5 | 2044410441422423 |
6 | 50454230153533 |
7 | 4563560313324 |
oct | 763743754601 |
9 | 212172302643 |
10 | 67101514113 |
11 | 26504067797 |
12 | 110081b28a9 |
13 | 6434ab6b4a |
14 | 3367ab67bb |
15 | 1b2ae20193 |
hex | f9f8fd981 |
67101514113 has 16 divisors (see below), whose sum is σ = 94739633856. Its totient is φ = 42099317760.
The previous prime is 67101514069. The next prime is 67101514157. The reversal of 67101514113 is 31141510176.
It is an interprime number because it is at equal distance from previous prime (67101514069) and next prime (67101514157).
It is not a de Polignac number, because 67101514113 - 29 = 67101513601 is a prime.
It is a super-2 number, since 2×671015141132 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (67101514913) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 628345 + ... + 727337.
It is an arithmetic number, because the mean of its divisors is an integer number (5921227116).
Almost surely, 267101514113 is an apocalyptic number.
It is an amenable number.
67101514113 is a deficient number, since it is larger than the sum of its proper divisors (27638119743).
67101514113 is a wasteful number, since it uses less digits than its factorization.
67101514113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 112304.
The product of its (nonzero) digits is 2520, while the sum is 30.
The spelling of 67101514113 in words is "sixty-seven billion, one hundred one million, five hundred fourteen thousand, one hundred thirteen".
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