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671065222561493 is a prime number
BaseRepresentation
bin1001100010010101001000110…
…0001101100011111011010101
310021000001012122011200210021112
42120211102030031203323111
51200424213033433431433
610335123035104224405
7261230601540266564
oct23045221415437325
93230035564623245
10671065222561493
11184905187557841
1263320b2930b105
1322a5a2432214c6
14bb9da31467bdb
15528ae2e3e8348
hex262548c363ed5

671065222561493 has 2 divisors, whose sum is σ = 671065222561494. Its totient is φ = 671065222561492.

The previous prime is 671065222561441. The next prime is 671065222561511. The reversal of 671065222561493 is 394165222560176.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 646374589514404 + 24690633047089 = 25423898^2 + 4968967^2 .

It is a cyclic number.

It is not a de Polignac number, because 671065222561493 - 26 = 671065222561429 is a prime.

It is a super-2 number, since 2×6710652225614932 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (671065224561493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335532611280746 + 335532611280747.

It is an arithmetic number, because the mean of its divisors is an integer number (335532611280747).

Almost surely, 2671065222561493 is an apocalyptic number.

It is an amenable number.

671065222561493 is a deficient number, since it is larger than the sum of its proper divisors (1).

671065222561493 is an equidigital number, since it uses as much as digits as its factorization.

671065222561493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32659200, while the sum is 59.

The spelling of 671065222561493 in words is "six hundred seventy-one trillion, sixty-five billion, two hundred twenty-two million, five hundred sixty-one thousand, four hundred ninety-three".