Base | Representation |
---|---|
bin | 1001100010010111010110011… |
… | …0010110110000011010111111 |
3 | 10021000011211202211020122220121 |
4 | 2120211311212112300122333 |
5 | 1200430323414442042143 |
6 | 10335152323455555411 |
7 | 261233415646354015 |
oct | 23045654626603277 |
9 | 3230154684218817 |
10 | 671103242143423 |
11 | 18491a317623431 |
12 | 63328379b2bb67 |
13 | 22a609c1bc474b |
14 | bba17da9d68b5 |
15 | 528be070d97ed |
hex | 2625d665b06bf |
671103242143423 has 2 divisors, whose sum is σ = 671103242143424. Its totient is φ = 671103242143422.
The previous prime is 671103242143417. The next prime is 671103242143517. The reversal of 671103242143423 is 324341242301176.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 671103242143423 - 237 = 670965803189951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 671103242143423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (671103242149423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335551621071711 + 335551621071712.
It is an arithmetic number, because the mean of its divisors is an integer number (335551621071712).
Almost surely, 2671103242143423 is an apocalyptic number.
671103242143423 is a deficient number, since it is larger than the sum of its proper divisors (1).
671103242143423 is an equidigital number, since it uses as much as digits as its factorization.
671103242143423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 43.
Adding to 671103242143423 its reverse (324341242301176), we get a palindrome (995444484444599).
The spelling of 671103242143423 in words is "six hundred seventy-one trillion, one hundred three billion, two hundred forty-two million, one hundred forty-three thousand, four hundred twenty-three".
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