Search a number
-
+
671150238851 is a prime number
BaseRepresentation
bin10011100010000111010…
…10111110110010000011
32101011100121120200102202
421301003222332302003
541444003430120401
61232153330503415
766326504621501
oct11610352766203
92334317520382
10671150238851
112396a68a4094
12aa0a6a34b6b
134b39b495861
14246ab955671
15126d143a06b
hex9c43abec83

671150238851 has 2 divisors, whose sum is σ = 671150238852. Its totient is φ = 671150238850.

The previous prime is 671150238833. The next prime is 671150238853. The reversal of 671150238851 is 158832051176.

671150238851 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 671150238851 - 226 = 671083129987 is a prime.

It is a Sophie Germain prime.

Together with 671150238853, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 671150238796 and 671150238805.

It is not a weakly prime, because it can be changed into another prime (671150238853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335575119425 + 335575119426.

It is an arithmetic number, because the mean of its divisors is an integer number (335575119426).

Almost surely, 2671150238851 is an apocalyptic number.

671150238851 is a deficient number, since it is larger than the sum of its proper divisors (1).

671150238851 is an equidigital number, since it uses as much as digits as its factorization.

671150238851 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 403200, while the sum is 47.

The spelling of 671150238851 in words is "six hundred seventy-one billion, one hundred fifty million, two hundred thirty-eight thousand, eight hundred fifty-one".