67125433 has 2 divisors, whose sum is σ = 67125434. Its totient is φ = 67125432.

The previous prime is 67125427. The next prime is 67125439. The reversal of 67125433 is 33452176.

It is a balanced prime because it is at equal distance from previous prime (67125427) and next prime (67125439).

It can be written as a sum of positive squares in only one way, i.e., 64208169 + 2917264 = 8013^2 + 1708^2 .

It is a cyclic number.

It is not a de Polignac number, because 67125433 - 2⁹ = 67124921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 67125395 and 67125404.

It is not a weakly prime, because it can be changed into another prime (67125439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33562716 + 33562717.

It is an arithmetic number, because the mean of its divisors is an integer number (33562717).

Almost surely, 2^67125433 is an apocalyptic number.

It is an amenable number.

67125433 is a deficient number, since it is larger than the sum of its proper divisors (1).

67125433 is an equidigital number, since it uses as much as digits as its factorization.

67125433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15120, while the sum is 31.

The square root of 67125433 is about 8193.0112290903. The cubic root of 67125433 is about 406.4081108267.

The spelling of 67125433 in words is "sixty-seven million, one hundred twenty-five thousand, four hundred thirty-three".