Base | Representation |
---|---|
bin | 111110100001111011… |
… | …100001000000010011 |
3 | 20102022012002112100222 |
4 | 332201323201000103 |
5 | 2100001124233044 |
6 | 50502205503255 |
7 | 4564552101563 |
oct | 764173410023 |
9 | 212265075328 |
10 | 67141242899 |
11 | 265245325a5 |
12 | 11019571b2b |
13 | 64400b70c3 |
14 | 336d098da3 |
15 | 1b2e66b8ee |
hex | fa1ee1013 |
67141242899 has 2 divisors, whose sum is σ = 67141242900. Its totient is φ = 67141242898.
The previous prime is 67141242887. The next prime is 67141242907. The reversal of 67141242899 is 99824214176.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-67141242899 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 67141242899.
It is not a weakly prime, because it can be changed into another prime (67141242809) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33570621449 + 33570621450.
It is an arithmetic number, because the mean of its divisors is an integer number (33570621450).
Almost surely, 267141242899 is an apocalyptic number.
67141242899 is a deficient number, since it is larger than the sum of its proper divisors (1).
67141242899 is an equidigital number, since it uses as much as digits as its factorization.
67141242899 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1741824, while the sum is 53.
The spelling of 67141242899 in words is "sixty-seven billion, one hundred forty-one million, two hundred forty-two thousand, eight hundred ninety-nine".
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