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673440113 is a prime number
BaseRepresentation
bin101000001000111…
…110000101110001
31201221012022011102
4220020332011301
52334400040423
6150454054145
722455101153
oct5010760561
91657168142
10673440113
11316159585
1216964a355
13a96a0198
1465622ad3
153e1c7c28
hex2823e171

673440113 has 2 divisors, whose sum is σ = 673440114. Its totient is φ = 673440112.

The previous prime is 673440109. The next prime is 673440121. The reversal of 673440113 is 311044376.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 440664064 + 232776049 = 20992^2 + 15257^2 .

It is a cyclic number.

It is not a de Polignac number, because 673440113 - 22 = 673440109 is a prime.

It is not a weakly prime, because it can be changed into another prime (673440413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336720056 + 336720057.

It is an arithmetic number, because the mean of its divisors is an integer number (336720057).

Almost surely, 2673440113 is an apocalyptic number.

It is an amenable number.

673440113 is a deficient number, since it is larger than the sum of its proper divisors (1).

673440113 is an equidigital number, since it uses as much as digits as its factorization.

673440113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

The square root of 673440113 is about 25950.7247104970. The cubic root of 673440113 is about 876.5290762363.

Adding to 673440113 its reverse (311044376), we get a palindrome (984484489).

The spelling of 673440113 in words is "six hundred seventy-three million, four hundred forty thousand, one hundred thirteen".