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673989036239093 is a prime number
BaseRepresentation
bin1001100100111111010100110…
…1000101100110100011110101
310021101101201111202221212220012
42121033311031011212203311
51201320114021234122333
610345242142214350005
7261652046424425651
oct23117651505464365
93241351452855805
10673989036239093
1118583216610a903
126371371065b305
1322c0cb7ca62463
14bc61359cb7a61
1552dc00538be48
hex264fd4d1668f5

673989036239093 has 2 divisors, whose sum is σ = 673989036239094. Its totient is φ = 673989036239092.

The previous prime is 673989036239059. The next prime is 673989036239117. The reversal of 673989036239093 is 390932630989376.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 615646906446289 + 58342129792804 = 24812233^2 + 7638202^2 .

It is a cyclic number.

It is not a de Polignac number, because 673989036239093 - 220 = 673989035190517 is a prime.

It is a super-2 number, since 2×6739890362390932 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (673989036235093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336994518119546 + 336994518119547.

It is an arithmetic number, because the mean of its divisors is an integer number (336994518119547).

Almost surely, 2673989036239093 is an apocalyptic number.

It is an amenable number.

673989036239093 is a deficient number, since it is larger than the sum of its proper divisors (1).

673989036239093 is an equidigital number, since it uses as much as digits as its factorization.

673989036239093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2142770112, while the sum is 77.

The spelling of 673989036239093 in words is "six hundred seventy-three trillion, nine hundred eighty-nine billion, thirty-six million, two hundred thirty-nine thousand, ninety-three".