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6740213466719 is a prime number
BaseRepresentation
bin110001000010101010000…
…0001111000011001011111
3212212100200001202201102102
41202011110001320121133
51340412424121413334
622200224502315315
71263651526111355
oct142052401703137
925770601681372
106740213466719
11216956586a867
1290a36ba28b3b
1339b7a3b70055
14194329b8b7d5
15ba4dd64167e
hex6215407865f

6740213466719 has 2 divisors, whose sum is σ = 6740213466720. Its totient is φ = 6740213466718.

The previous prime is 6740213466643. The next prime is 6740213466757. The reversal of 6740213466719 is 9176643120476.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 6740213466719 - 212 = 6740213462623 is a prime.

It is a super-3 number, since 3×67402134667193 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6740213463719) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3370106733359 + 3370106733360.

It is an arithmetic number, because the mean of its divisors is an integer number (3370106733360).

Almost surely, 26740213466719 is an apocalyptic number.

6740213466719 is a deficient number, since it is larger than the sum of its proper divisors (1).

6740213466719 is an equidigital number, since it uses as much as digits as its factorization.

6740213466719 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9144576, while the sum is 56.

The spelling of 6740213466719 in words is "six trillion, seven hundred forty billion, two hundred thirteen million, four hundred sixty-six thousand, seven hundred nineteen".