Base | Representation |
---|---|
bin | 110001000010111111001… |
… | …1110010110011100011101 |
3 | 212212102111200201110110011 |
4 | 1202011332132112130131 |
5 | 1340420403421313033 |
6 | 22200423301243221 |
7 | 1264005263653561 |
oct | 142057636263435 |
9 | 25772450643404 |
10 | 6740925572893 |
11 | 21698a0828766 |
12 | 90a52a403511 |
13 | 39b88855a855 |
14 | 1943965976a1 |
15 | ba530e05ccd |
hex | 6217e79671d |
6740925572893 has 2 divisors, whose sum is σ = 6740925572894. Its totient is φ = 6740925572892.
The previous prime is 6740925572869. The next prime is 6740925572929. The reversal of 6740925572893 is 3982755290476.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5965210294884 + 775715278009 = 2442378^2 + 880747^2 .
It is a cyclic number.
It is not a de Polignac number, because 6740925572893 - 217 = 6740925441821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6740925579893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3370462786446 + 3370462786447.
It is an arithmetic number, because the mean of its divisors is an integer number (3370462786447).
Almost surely, 26740925572893 is an apocalyptic number.
It is an amenable number.
6740925572893 is a deficient number, since it is larger than the sum of its proper divisors (1).
6740925572893 is an equidigital number, since it uses as much as digits as its factorization.
6740925572893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 228614400, while the sum is 67.
The spelling of 6740925572893 in words is "six trillion, seven hundred forty billion, nine hundred twenty-five million, five hundred seventy-two thousand, eight hundred ninety-three".
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