Base | Representation |
---|---|
bin | 111110110010000100… |
… | …111110111110110001 |
3 | 20110000001212120100201 |
4 | 332302010332332301 |
5 | 2101030003113213 |
6 | 50545124315201 |
7 | 4604351623612 |
oct | 766204767661 |
9 | 213001776321 |
10 | 67412160433 |
11 | 26653452992 |
12 | 11094242b01 |
13 | 6484271737 |
14 | 339705bc09 |
15 | 1b483336dd |
hex | fb213efb1 |
67412160433 has 8 divisors (see below), whose sum is σ = 68085372096. Its totient is φ = 66739062000.
The previous prime is 67412160419. The next prime is 67412160467. The reversal of 67412160433 is 33406121476.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 67412160433 - 25 = 67412160401 is a prime.
It is a super-3 number, since 3×674121604333 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 67412160392 and 67412160401.
It is not an unprimeable number, because it can be changed into a prime (67412160133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1678060 + ... + 1717762.
It is an arithmetic number, because the mean of its divisors is an integer number (8510671512).
Almost surely, 267412160433 is an apocalyptic number.
It is an amenable number.
67412160433 is a deficient number, since it is larger than the sum of its proper divisors (673211663).
67412160433 is a wasteful number, since it uses less digits than its factorization.
67412160433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56615.
The product of its (nonzero) digits is 72576, while the sum is 37.
The spelling of 67412160433 in words is "sixty-seven billion, four hundred twelve million, one hundred sixty thousand, four hundred thirty-three".
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