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674128000069 is a prime number
BaseRepresentation
bin10011100111101010010…
…10001111010001000101
32101110001010202121220021
421303311022033101011
542021103232000234
61233405022335141
766463343312206
oct11636512172105
92343033677807
10674128000069
1123a994755177
12aa79812a4b1
134b754391944
14248b120d5ad
1512807a899b4
hex9cf528f445

674128000069 has 2 divisors, whose sum is σ = 674128000070. Its totient is φ = 674128000068.

The previous prime is 674128000009. The next prime is 674128000099. The reversal of 674128000069 is 960000821476.

674128000069 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 637594265025 + 36533735044 = 798495^2 + 191138^2 .

It is a cyclic number.

It is not a de Polignac number, because 674128000069 - 29 = 674127999557 is a prime.

It is a super-2 number, since 2×6741280000692 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 674127999989 and 674128000034.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (674128000009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 337064000034 + 337064000035.

It is an arithmetic number, because the mean of its divisors is an integer number (337064000035).

Almost surely, 2674128000069 is an apocalyptic number.

It is an amenable number.

674128000069 is a deficient number, since it is larger than the sum of its proper divisors (1).

674128000069 is an equidigital number, since it uses as much as digits as its factorization.

674128000069 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 43.

The spelling of 674128000069 in words is "six hundred seventy-four billion, one hundred twenty-eight million, sixty-nine", and thus it is an aban number.