Base | Representation |
---|---|
bin | 11110101010000100010011… |
… | …11101101111000010001111 |
3 | 22211200220210102001210101201 |
4 | 33111002021331233002033 |
5 | 32314021204030340142 |
6 | 355214312200250331 |
7 | 20125440222302224 |
oct | 1725021175570217 |
9 | 284626712053351 |
10 | 67416121340047 |
11 | 1a53201aa64177 |
12 | 76898427709a7 |
13 | 2b8040b7741cc |
14 | 1290d59c4b94b |
15 | 7bd9ac15dab7 |
hex | 3d5089f6f08f |
67416121340047 has 2 divisors, whose sum is σ = 67416121340048. Its totient is φ = 67416121340046.
The previous prime is 67416121339967. The next prime is 67416121340053. The reversal of 67416121340047 is 74004312161476.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 67416121340047 - 239 = 66866365526159 is a prime.
It is a super-2 number, since 2×674161213400472 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 67416121339979 and 67416121340006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (67416121340147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33708060670023 + 33708060670024.
It is an arithmetic number, because the mean of its divisors is an integer number (33708060670024).
Almost surely, 267416121340047 is an apocalyptic number.
67416121340047 is a deficient number, since it is larger than the sum of its proper divisors (1).
67416121340047 is an equidigital number, since it uses as much as digits as its factorization.
67416121340047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 677376, while the sum is 46.
The spelling of 67416121340047 in words is "sixty-seven trillion, four hundred sixteen billion, one hundred twenty-one million, three hundred forty thousand, forty-seven".
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