Base | Representation |
---|---|
bin | 111111010110001001… |
… | …001010010111001011 |
3 | 20111120020102120011210 |
4 | 333112021022113023 |
5 | 2103244403013103 |
6 | 51125141224203 |
7 | 4625346650565 |
oct | 772611122713 |
9 | 214506376153 |
10 | 68017235403 |
11 | 26933a57747 |
12 | 11222a02063 |
13 | 654c726270 |
14 | 3413566335 |
15 | 1b81504e03 |
hex | fd624a5cb |
68017235403 has 8 divisors (see below), whose sum is σ = 97665773968. Its totient is φ = 41856760224.
The previous prime is 68017235371. The next prime is 68017235449. The reversal of 68017235403 is 30453271086.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 68017235403 - 25 = 68017235371 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39), and also a Moran number because the ratio is a prime number: 1744031677 = 68017235403 / (6 + 8 + 0 + 1 + 7 + 2 + 3 + 5 + 4 + 0 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (68017235203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 872015800 + ... + 872015877.
It is an arithmetic number, because the mean of its divisors is an integer number (12208221746).
Almost surely, 268017235403 is an apocalyptic number.
68017235403 is a deficient number, since it is larger than the sum of its proper divisors (29648538565).
68017235403 is a wasteful number, since it uses less digits than its factorization.
68017235403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1744031693.
The product of its (nonzero) digits is 120960, while the sum is 39.
The spelling of 68017235403 in words is "sixty-eight billion, seventeen million, two hundred thirty-five thousand, four hundred three".
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