Search a number
-
+
6804000089 is a prime number
BaseRepresentation
bin1100101011000110…
…01100110101011001
3122120011221000110022
412111203030311121
5102413311000324
63043053200225
7330416021645
oct62543146531
918504830408
106804000089
112981753a77
12139a790075
1384581c573
144878d9c25
1529c50005e
hex1958ccd59

6804000089 has 2 divisors, whose sum is σ = 6804000090. Its totient is φ = 6804000088.

The previous prime is 6804000011. The next prime is 6804000101. The reversal of 6804000089 is 9800004086.

6804000089 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6612454489 + 191545600 = 81317^2 + 13840^2 .

It is a cyclic number.

It is not a de Polignac number, because 6804000089 - 220 = 6802951513 is a prime.

It is a super-2 number, since 2×68040000892 = 92588834422224015842, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (6804000589) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3402000044 + 3402000045.

It is an arithmetic number, because the mean of its divisors is an integer number (3402000045).

Almost surely, 26804000089 is an apocalyptic number.

It is an amenable number.

6804000089 is a deficient number, since it is larger than the sum of its proper divisors (1).

6804000089 is an equidigital number, since it uses as much as digits as its factorization.

6804000089 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 35.

The square root of 6804000089 is about 82486.3630486882. The cubic root of 6804000089 is about 1894.9078875591.

The spelling of 6804000089 in words is "six billion, eight hundred four million, eighty-nine", and thus it is an aban number.