Base | Representation |
---|---|
bin | 1001101101011000001011111… |
… | …1000000001101010011010011 |
3 | 10022121001110012212011222002212 |
4 | 2123112002333000031103103 |
5 | 1204022222133001241201 |
6 | 10421023212055502335 |
7 | 263623312160603126 |
oct | 23326027700152323 |
9 | 3277043185158085 |
10 | 683212242212051 |
11 | 188768759471082 |
12 | 647631396879ab |
13 | 2342b83a899356 |
14 | c09d912a683bd |
15 | 53ebdb9436abb |
hex | 26d60bf00d4d3 |
683212242212051 has 2 divisors, whose sum is σ = 683212242212052. Its totient is φ = 683212242212050.
The previous prime is 683212242212033. The next prime is 683212242212053. The reversal of 683212242212051 is 150212242212386.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 683212242212051 - 218 = 683212241949907 is a prime.
Together with 683212242212053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (683212242212053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 341606121106025 + 341606121106026.
It is an arithmetic number, because the mean of its divisors is an integer number (341606121106026).
Almost surely, 2683212242212051 is an apocalyptic number.
683212242212051 is a deficient number, since it is larger than the sum of its proper divisors (1).
683212242212051 is an equidigital number, since it uses as much as digits as its factorization.
683212242212051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 184320, while the sum is 41.
The spelling of 683212242212051 in words is "six hundred eighty-three trillion, two hundred twelve billion, two hundred forty-two million, two hundred twelve thousand, fifty-one".
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