Base | Representation |
---|---|
bin | 111111101100101011… |
… | …011010100110000111 |
3 | 20112112120211220212212 |
4 | 333230223122212013 |
5 | 2110033200013133 |
6 | 51230444534035 |
7 | 4640620400324 |
oct | 775453324607 |
9 | 215476756785 |
10 | 68395313543 |
11 | 2700840a417 |
12 | 1130955131b |
13 | 65acb6073b |
14 | 344b861b4b |
15 | 1ba47d8148 |
hex | fecada987 |
68395313543 has 2 divisors, whose sum is σ = 68395313544. Its totient is φ = 68395313542.
The previous prime is 68395313533. The next prime is 68395313549. The reversal of 68395313543 is 34531359386.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 68395313543 - 210 = 68395312519 is a prime.
It is a super-4 number, since 4×683953135434 (a number of 44 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 68395313491 and 68395313500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (68395313549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34197656771 + 34197656772.
It is an arithmetic number, because the mean of its divisors is an integer number (34197656772).
Almost surely, 268395313543 is an apocalyptic number.
68395313543 is a deficient number, since it is larger than the sum of its proper divisors (1).
68395313543 is an equidigital number, since it uses as much as digits as its factorization.
68395313543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3499200, while the sum is 50.
The spelling of 68395313543 in words is "sixty-eight billion, three hundred ninety-five million, three hundred thirteen thousand, five hundred forty-three".
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