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6893101240457 is a prime number
BaseRepresentation
bin110010001001110110011…
…0110011101000010001001
3220101222022002002100010212
41210103230312131002021
51400414032404143312
622354351430050505
71311003321542135
oct144235466350211
926358262070125
106893101240457
112218390a47083
12933b197a9a35
133b002a79c263
1419b8b0c903c5
15be48a9e7822
hex644ecd9d089

6893101240457 has 2 divisors, whose sum is σ = 6893101240458. Its totient is φ = 6893101240456.

The previous prime is 6893101240453. The next prime is 6893101240471. The reversal of 6893101240457 is 7540421013986.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6502112405776 + 390988834681 = 2549924^2 + 625291^2 .

It is a cyclic number.

It is not a de Polignac number, because 6893101240457 - 22 = 6893101240453 is a prime.

It is a super-2 number, since 2×68931012404572 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (6893101240453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3446550620228 + 3446550620229.

It is an arithmetic number, because the mean of its divisors is an integer number (3446550620229).

It is a 1-persistent number, because it is pandigital, but 2⋅6893101240457 = 13786202480914 is not.

Almost surely, 26893101240457 is an apocalyptic number.

It is an amenable number.

6893101240457 is a deficient number, since it is larger than the sum of its proper divisors (1).

6893101240457 is an equidigital number, since it uses as much as digits as its factorization.

6893101240457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 6893101240457 in words is "six trillion, eight hundred ninety-three billion, one hundred one million, two hundred forty thousand, four hundred fifty-seven".