Base | Representation |
---|---|
bin | 110010011100100000000… |
… | …0100100001011010110111 |
3 | 220112210200021220222211212 |
4 | 1210321000010201122313 |
5 | 1402043043422034111 |
6 | 22425013543552035 |
7 | 1313621654600012 |
oct | 144710004413267 |
9 | 26483607828755 |
10 | 6933152143031 |
11 | 2233373701a64 |
12 | 93b83675b61b |
13 | 3b3a4126498a |
14 | 19d7d010c379 |
15 | c0531bd698b |
hex | 64e401216b7 |
6933152143031 has 2 divisors, whose sum is σ = 6933152143032. Its totient is φ = 6933152143030.
The previous prime is 6933152142953. The next prime is 6933152143063. The reversal of 6933152143031 is 1303412513396.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6933152143031 - 214 = 6933152126647 is a prime.
It is a super-2 number, since 2×69331521430312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 6933152143031.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6933652143031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3466576071515 + 3466576071516.
It is an arithmetic number, because the mean of its divisors is an integer number (3466576071516).
Almost surely, 26933152143031 is an apocalyptic number.
6933152143031 is a deficient number, since it is larger than the sum of its proper divisors (1).
6933152143031 is an equidigital number, since it uses as much as digits as its factorization.
6933152143031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174960, while the sum is 41.
The spelling of 6933152143031 in words is "six trillion, nine hundred thirty-three billion, one hundred fifty-two million, one hundred forty-three thousand, thirty-one".
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