Base | Representation |
---|---|
bin | 100000010100101001… |
… | …0100111110000000001 |
3 | 20122011110100022210011 |
4 | 1000221102213300001 |
5 | 2114124012132001 |
6 | 51515412504521 |
7 | 5005046112001 |
oct | 1005122476001 |
9 | 218143308704 |
10 | 69412224001 |
11 | 2748a43328a |
12 | 1155201b141 |
13 | 671273b9c3 |
14 | 3506932001 |
15 | 1c13c09d51 |
hex | 10294a7c01 |
69412224001 has 2 divisors, whose sum is σ = 69412224002. Its totient is φ = 69412224000.
The previous prime is 69412223977. The next prime is 69412224061. The reversal of 69412224001 is 10042221496.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44342251776 + 25069972225 = 210576^2 + 158335^2 .
It is a cyclic number.
It is not a de Polignac number, because 69412224001 - 213 = 69412215809 is a prime.
It is not a weakly prime, because it can be changed into another prime (69412224061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34706112000 + 34706112001.
It is an arithmetic number, because the mean of its divisors is an integer number (34706112001).
Almost surely, 269412224001 is an apocalyptic number.
It is an amenable number.
69412224001 is a deficient number, since it is larger than the sum of its proper divisors (1).
69412224001 is an equidigital number, since it uses as much as digits as its factorization.
69412224001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 69412224001 its reverse (10042221496), we get a palindrome (79454445497).
The spelling of 69412224001 in words is "sixty-nine billion, four hundred twelve million, two hundred twenty-four thousand, one".
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