Base | Representation |
---|---|
bin | 110010100000101011000… |
… | …1111101110001110001101 |
3 | 220120122210212110012122012 |
4 | 1211001112033232032031 |
5 | 1402214422203044042 |
6 | 22433055130031005 |
7 | 1314360026224412 |
oct | 145012617561615 |
9 | 26518725405565 |
10 | 6942114112397 |
11 | 2237152488212 |
12 | 941517b78465 |
13 | 3b483bb8a929 |
14 | 1a0000464109 |
15 | c08a889ee82 |
hex | 650563ee38d |
6942114112397 has 2 divisors, whose sum is σ = 6942114112398. Its totient is φ = 6942114112396.
The previous prime is 6942114112387. The next prime is 6942114112459. The reversal of 6942114112397 is 7932114112496.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5703981666601 + 1238132445796 = 2388301^2 + 1112714^2 .
It is a cyclic number.
It is not a de Polignac number, because 6942114112397 - 214 = 6942114096013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6942114112357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3471057056198 + 3471057056199.
It is an arithmetic number, because the mean of its divisors is an integer number (3471057056199).
Almost surely, 26942114112397 is an apocalyptic number.
It is an amenable number.
6942114112397 is a deficient number, since it is larger than the sum of its proper divisors (1).
6942114112397 is an equidigital number, since it uses as much as digits as its factorization.
6942114112397 is an evil number, because the sum of its binary digits is even.
The product of its digits is 653184, while the sum is 50.
Subtracting 6942114112397 from its reverse (7932114112496), we obtain a palindrome (990000000099).
The spelling of 6942114112397 in words is "six trillion, nine hundred forty-two billion, one hundred fourteen million, one hundred twelve thousand, three hundred ninety-seven".
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