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694314323413853 is a prime number
BaseRepresentation
bin1001110111011110011010011…
…0100111000000101101011101
310101001100210121222121222211012
42131313212212213000231131
51212001121213243220403
610500403332525505005
7266150361122016632
oct23567464647005535
93331323558558735
10694314323413853
1119125906191487a
1265a56926112165
1323a55737a3859c
14c364dc7816189
155540a978cced8
hex27779a69c0b5d

694314323413853 has 2 divisors, whose sum is σ = 694314323413854. Its totient is φ = 694314323413852.

The previous prime is 694314323413801. The next prime is 694314323413871. The reversal of 694314323413853 is 358314323413496.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 517498210496569 + 176816112917284 = 22748587^2 + 13297222^2 .

It is a cyclic number.

It is not a de Polignac number, because 694314323413853 - 28 = 694314323413597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 694314323413792 and 694314323413801.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (694314323413873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 347157161706926 + 347157161706927.

It is an arithmetic number, because the mean of its divisors is an integer number (347157161706927).

Almost surely, 2694314323413853 is an apocalyptic number.

It is an amenable number.

694314323413853 is a deficient number, since it is larger than the sum of its proper divisors (1).

694314323413853 is an equidigital number, since it uses as much as digits as its factorization.

694314323413853 is an evil number, because the sum of its binary digits is even.

The product of its digits is 67184640, while the sum is 59.

The spelling of 694314323413853 in words is "six hundred ninety-four trillion, three hundred fourteen billion, three hundred twenty-three million, four hundred thirteen thousand, eight hundred fifty-three".