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69514454081 is a prime number
BaseRepresentation
bin100000010111101100…
…0100110010001000001
320122102120201011002102
41000233120212101001
52114331200012311
651533504000145
75010430052612
oct1005730462101
9218376634072
1069514454081
1127532108256
1211580300055
13672a983587
143516343c09
151c1cba043b
hex102f626441

69514454081 has 2 divisors, whose sum is σ = 69514454082. Its totient is φ = 69514454080.

The previous prime is 69514453991. The next prime is 69514454083. The reversal of 69514454081 is 18045441596.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 58447414081 + 11067040000 = 241759^2 + 105200^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-69514454081 is a prime.

It is a super-2 number, since 2×695144540812 (a number of 22 digits) contains 22 as substring.

Together with 69514454083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (69514454083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34757227040 + 34757227041.

It is an arithmetic number, because the mean of its divisors is an integer number (34757227041).

Almost surely, 269514454081 is an apocalyptic number.

It is an amenable number.

69514454081 is a deficient number, since it is larger than the sum of its proper divisors (1).

69514454081 is an equidigital number, since it uses as much as digits as its factorization.

69514454081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 691200, while the sum is 47.

The spelling of 69514454081 in words is "sixty-nine billion, five hundred fourteen million, four hundred fifty-four thousand, eighty-one".