Base | Representation |
---|---|
bin | 110011101010011001010… |
… | …1000110001100110010111 |
3 | 221010210110012122110220022 |
4 | 1213110302220301212113 |
5 | 1412313140201140012 |
6 | 23033520455255355 |
7 | 1331663200226501 |
oct | 147246250614627 |
9 | 27123405573808 |
10 | 7100430490007 |
11 | 22983039a3a08 |
12 | 96813b97a55b |
13 | 3c674c39368a |
14 | 1a793c516d71 |
15 | c4a72621472 |
hex | 67532a31997 |
7100430490007 has 2 divisors, whose sum is σ = 7100430490008. Its totient is φ = 7100430490006.
The previous prime is 7100430489941. The next prime is 7100430490019. The reversal of 7100430490007 is 7000940340017.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 7100430490007 - 232 = 7096135522711 is a prime.
It is a super-2 number, since 2×71004304900072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (7100430490067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3550215245003 + 3550215245004.
It is an arithmetic number, because the mean of its divisors is an integer number (3550215245004).
Almost surely, 27100430490007 is an apocalyptic number.
7100430490007 is a deficient number, since it is larger than the sum of its proper divisors (1).
7100430490007 is an equidigital number, since it uses as much as digits as its factorization.
7100430490007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21168, while the sum is 35.
The spelling of 7100430490007 in words is "seven trillion, one hundred billion, four hundred thirty million, four hundred ninety thousand, seven".
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