Base | Representation |
---|---|
bin | 10000001001101001000001… |
… | …101111000101010010000101 |
3 | 100022111112010110211112022121 |
4 | 100021221001233011102011 |
5 | 33302234021113041233 |
6 | 411023152121325541 |
7 | 20650561065023422 |
oct | 2011510157052205 |
9 | 308445113745277 |
10 | 71031272002693 |
11 | 206a621429a542 |
12 | 7b724053368b1 |
13 | 30832b2a4c042 |
14 | 1377d0922ad49 |
15 | 832a4689592d |
hex | 409a41bc5485 |
71031272002693 has 2 divisors, whose sum is σ = 71031272002694. Its totient is φ = 71031272002692.
The previous prime is 71031272002673. The next prime is 71031272002709. The reversal of 71031272002693 is 39620027213017.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54037230404004 + 16994041598689 = 7351002^2 + 4122383^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-71031272002693 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (71031272002643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35515636001346 + 35515636001347.
It is an arithmetic number, because the mean of its divisors is an integer number (35515636001347).
Almost surely, 271031272002693 is an apocalyptic number.
It is an amenable number.
71031272002693 is a deficient number, since it is larger than the sum of its proper divisors (1).
71031272002693 is an equidigital number, since it uses as much as digits as its factorization.
71031272002693 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 190512, while the sum is 43.
The spelling of 71031272002693 in words is "seventy-one trillion, thirty-one billion, two hundred seventy-two million, two thousand, six hundred ninety-three".
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