Base | Representation |
---|---|
bin | 10000001001110011111111… |
… | …110100011001000100111111 |
3 | 100022112122112101002121010211 |
4 | 100021303333310121010333 |
5 | 33302432132024001002 |
6 | 411032421014213251 |
7 | 20651456013610003 |
oct | 2011637764310477 |
9 | 308478471077124 |
10 | 71043051000127 |
11 | 20700209223668 |
12 | 7b74752054227 |
13 | 308443c1849cb |
14 | 137870575a703 |
15 | 832ed5a0ddd7 |
hex | 409cffd1913f |
71043051000127 has 2 divisors, whose sum is σ = 71043051000128. Its totient is φ = 71043051000126.
The previous prime is 71043051000029. The next prime is 71043051000133. The reversal of 71043051000127 is 72100015034017.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-71043051000127 is a prime.
It is a super-2 number, since 2×710430510001272 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (71043051000157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35521525500063 + 35521525500064.
It is an arithmetic number, because the mean of its divisors is an integer number (35521525500064).
Almost surely, 271043051000127 is an apocalyptic number.
71043051000127 is a deficient number, since it is larger than the sum of its proper divisors (1).
71043051000127 is an equidigital number, since it uses as much as digits as its factorization.
71043051000127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5880, while the sum is 31.
The spelling of 71043051000127 in words is "seventy-one trillion, forty-three billion, fifty-one million, one hundred twenty-seven", and thus it is an aban number.
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