71233368094153 has 2 divisors, whose sum is σ = 71233368094154. Its totient is φ = 71233368094152.

The previous prime is 71233368094079. The next prime is 71233368094157. The reversal of 71233368094153 is 35149086333217.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68615842107024 + 2617525987129 = 8283468^2 + 1617877^2 .

It is an emirp because it is prime and its reverse (35149086333217) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 71233368094153 - 2¹³ = 71233368085961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 71233368094094 and 71233368094103.

It is not a weakly prime, because it can be changed into another prime (71233368094157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35616684047076 + 35616684047077.

It is an arithmetic number, because the mean of its divisors is an integer number (35616684047077).

It is a 1-persistent number, because it is pandigital, but 2⋅71233368094153 = 142466736188306 is not.

Almost surely, 2^{71233368094153} is an apocalyptic number.

It is an amenable number.

71233368094153 is a deficient number, since it is larger than the sum of its proper divisors (1).

71233368094153 is an equidigital number, since it uses as much as digits as its factorization.

71233368094153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9797760, while the sum is 55.

The spelling of 71233368094153 in words is "seventy-one trillion, two hundred thirty-three billion, three hundred sixty-eight million, ninety-four thousand, one hundred fifty-three".