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71300057471 = 83859036837
BaseRepresentation
bin100001001100111010…
…0001000100101111111
320211001000122012110022
41002121310020211333
52132010303314341
652431011402355
75102611326446
oct1023164104577
9224030565408
1071300057471
1128269029535
121199a2b33bb
1369538a2826
14364554dd5d
151cc4812e4b
hex1099d0897f

71300057471 has 4 divisors (see below), whose sum is σ = 72159094392. Its totient is φ = 70441020552.

The previous prime is 71300057447. The next prime is 71300057519. The reversal of 71300057471 is 17475000317.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 71300057471 - 26 = 71300057407 is a prime.

It is a super-3 number, since 3×713000574713 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (71300057441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 429518336 + ... + 429518501.

It is an arithmetic number, because the mean of its divisors is an integer number (18039773598).

Almost surely, 271300057471 is an apocalyptic number.

71300057471 is a deficient number, since it is larger than the sum of its proper divisors (859036921).

71300057471 is an equidigital number, since it uses as much as digits as its factorization.

71300057471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 859036920.

The product of its (nonzero) digits is 20580, while the sum is 35.

Adding to 71300057471 its reverse (17475000317), we get a palindrome (88775057788).

The spelling of 71300057471 in words is "seventy-one billion, three hundred million, fifty-seven thousand, four hundred seventy-one".

Divisors: 1 83 859036837 71300057471