Base | Representation |
---|---|
bin | 10100110000000101011… |
… | …00110111101100110101 |
3 | 2112011101212220012001121 |
4 | 22120002230313230311 |
5 | 43140221012404203 |
6 | 1303315140223541 |
7 | 102341023023211 |
oct | 12300254675465 |
9 | 2464355805047 |
10 | 713009888053 |
11 | 2554275480a1 |
12 | b622969abb1 |
13 | 5230c8c1558 |
14 | 2671d0c5941 |
15 | 1383130e0bd |
hex | a602b37b35 |
713009888053 has 2 divisors, whose sum is σ = 713009888054. Its totient is φ = 713009888052.
The previous prime is 713009888011. The next prime is 713009888081. The reversal of 713009888053 is 350888900317.
713009888053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 696635614609 + 16374273444 = 834647^2 + 127962^2 .
It is a cyclic number.
It is not a de Polignac number, because 713009888053 - 217 = 713009756981 is a prime.
It is a super-2 number, since 2×7130098880532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (713009888083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 356504944026 + 356504944027.
It is an arithmetic number, because the mean of its divisors is an integer number (356504944027).
Almost surely, 2713009888053 is an apocalyptic number.
It is an amenable number.
713009888053 is a deficient number, since it is larger than the sum of its proper divisors (1).
713009888053 is an equidigital number, since it uses as much as digits as its factorization.
713009888053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 52.
The spelling of 713009888053 in words is "seven hundred thirteen billion, nine million, eight hundred eighty-eight thousand, fifty-three".
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