Base | Representation |
---|---|
bin | 100001001110011001… |
… | …1000110111111100111 |
3 | 20211011111211122220201 |
4 | 1002130303012333213 |
5 | 2132111112323143 |
6 | 52440000411331 |
7 | 5104060005541 |
oct | 1023463067747 |
9 | 224144748821 |
10 | 71350120423 |
11 | 2829431257a |
12 | 119b3016b47 |
13 | 696108078a |
14 | 364c062691 |
15 | 1cc8e0164d |
hex | 109ccc6fe7 |
71350120423 has 2 divisors, whose sum is σ = 71350120424. Its totient is φ = 71350120422.
The previous prime is 71350120409. The next prime is 71350120433. The reversal of 71350120423 is 32402105317.
It is a strong prime.
It is an emirp because it is prime and its reverse (32402105317) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 71350120423 - 217 = 71349989351 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 71350120391 and 71350120400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (71350120403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35675060211 + 35675060212.
It is an arithmetic number, because the mean of its divisors is an integer number (35675060212).
Almost surely, 271350120423 is an apocalyptic number.
71350120423 is a deficient number, since it is larger than the sum of its proper divisors (1).
71350120423 is an equidigital number, since it uses as much as digits as its factorization.
71350120423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 28.
The spelling of 71350120423 in words is "seventy-one billion, three hundred fifty million, one hundred twenty thousand, four hundred twenty-three".
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