Base | Representation |
---|---|
bin | 110011111100000100111… |
… | …0100101110111100111111 |
3 | 221021102110101212001012102 |
4 | 1213320021310232330333 |
5 | 1413423421004332303 |
6 | 23103200315455315 |
7 | 1334506134543254 |
oct | 147701164567477 |
9 | 27242411761172 |
10 | 7138400464703 |
11 | 2302418a67992 |
12 | 973577a5753b |
13 | 3ca1c09b8221 |
14 | 1a970125142b |
15 | c5a45cb4288 |
hex | 67e09d2ef3f |
7138400464703 has 2 divisors, whose sum is σ = 7138400464704. Its totient is φ = 7138400464702.
The previous prime is 7138400464589. The next prime is 7138400464711. The reversal of 7138400464703 is 3074640048317.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 7138400464703 - 216 = 7138400399167 is a prime.
It is a super-2 number, since 2×71384004647032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (7138400464733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3569200232351 + 3569200232352.
It is an arithmetic number, because the mean of its divisors is an integer number (3569200232352).
Almost surely, 27138400464703 is an apocalyptic number.
7138400464703 is a deficient number, since it is larger than the sum of its proper divisors (1).
7138400464703 is an equidigital number, since it uses as much as digits as its factorization.
7138400464703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1354752, while the sum is 47.
The spelling of 7138400464703 in words is "seven trillion, one hundred thirty-eight billion, four hundred million, four hundred sixty-four thousand, seven hundred three".
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