Base | Representation |
---|---|
bin | 110011111100001011110… |
… | …0000101110110110100001 |
3 | 221021110001101221211221112 |
4 | 1213320113200232312201 |
5 | 1413424403301234213 |
6 | 23103235201433105 |
7 | 1334514623460104 |
oct | 147702740566641 |
9 | 27243041854845 |
10 | 7138630102433 |
11 | 2302526653135 |
12 | 97362093b795 |
13 | 3ca22944b63b |
14 | 1a972394a73b |
15 | c5a5b024ea8 |
hex | 67e1782eda1 |
7138630102433 has 2 divisors, whose sum is σ = 7138630102434. Its totient is φ = 7138630102432.
The previous prime is 7138630102411. The next prime is 7138630102469. The reversal of 7138630102433 is 3342010368317.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6992042197009 + 146587905424 = 2644247^2 + 382868^2 .
It is a cyclic number.
It is not a de Polignac number, because 7138630102433 - 228 = 7138361666977 is a prime.
It is not a weakly prime, because it can be changed into another prime (7138630102403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3569315051216 + 3569315051217.
It is an arithmetic number, because the mean of its divisors is an integer number (3569315051217).
Almost surely, 27138630102433 is an apocalyptic number.
It is an amenable number.
7138630102433 is a deficient number, since it is larger than the sum of its proper divisors (1).
7138630102433 is an equidigital number, since it uses as much as digits as its factorization.
7138630102433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 217728, while the sum is 41.
The spelling of 7138630102433 in words is "seven trillion, one hundred thirty-eight billion, six hundred thirty million, one hundred two thousand, four hundred thirty-three".
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