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714928344941 is a prime number
BaseRepresentation
bin10100110011101010000…
…11001100111101101101
32112100100120210220011102
422121311003030331231
543203133124014231
61304233351332445
7102436406444036
oct12316503147555
92470316726142
10714928344941
1125622145a158
12b6684081125
13525571b8045
1426861bd5a8d
15138e4965acb
hexa6750ccf6d

714928344941 has 2 divisors, whose sum is σ = 714928344942. Its totient is φ = 714928344940.

The previous prime is 714928344901. The next prime is 714928344953. The reversal of 714928344941 is 149443829417.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 709174515625 + 5753829316 = 842125^2 + 75854^2 .

It is a cyclic number.

It is not a de Polignac number, because 714928344941 - 210 = 714928343917 is a prime.

It is a super-3 number, since 3×7149283449413 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (714928344901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357464172470 + 357464172471.

It is an arithmetic number, because the mean of its divisors is an integer number (357464172471).

Almost surely, 2714928344941 is an apocalyptic number.

It is an amenable number.

714928344941 is a deficient number, since it is larger than the sum of its proper divisors (1).

714928344941 is an equidigital number, since it uses as much as digits as its factorization.

714928344941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6967296, while the sum is 56.

The spelling of 714928344941 in words is "seven hundred fourteen billion, nine hundred twenty-eight million, three hundred forty-four thousand, nine hundred forty-one".