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725305494913 is a prime number
BaseRepresentation
bin10101000110111111001…
…00111000110110000001
32120100010210020201210021
422203133210320312001
543340411201314123
61313111205533441
7103254513661426
oct12433744706601
92510123221707
10725305494913
1125a66705255a
12b869b414281
135351c07637c
1427168091d4d
1513d009c1c5d
hexa8df938d81

725305494913 has 2 divisors, whose sum is σ = 725305494914. Its totient is φ = 725305494912.

The previous prime is 725305494911. The next prime is 725305494959. The reversal of 725305494913 is 319494503527.

725305494913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 685663490304 + 39642004609 = 828048^2 + 199103^2 .

It is a cyclic number.

It is not a de Polignac number, because 725305494913 - 21 = 725305494911 is a prime.

Together with 725305494911, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (725305494911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 362652747456 + 362652747457.

It is an arithmetic number, because the mean of its divisors is an integer number (362652747457).

Almost surely, 2725305494913 is an apocalyptic number.

It is an amenable number.

725305494913 is a deficient number, since it is larger than the sum of its proper divisors (1).

725305494913 is an equidigital number, since it uses as much as digits as its factorization.

725305494913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4082400, while the sum is 52.

The spelling of 725305494913 in words is "seven hundred twenty-five billion, three hundred five million, four hundred ninety-four thousand, nine hundred thirteen".