Base | Representation |
---|---|
bin | 100001110011100111… |
… | …1010111111010000001 |
3 | 20221101112220112120212 |
4 | 1003213033113322001 |
5 | 2142140323344323 |
6 | 53203533243505 |
7 | 5150033455400 |
oct | 1034717277201 |
9 | 227345815525 |
10 | 72599043713 |
11 | 288752a4089 |
12 | 120a1333595 |
13 | 6acca44241 |
14 | 3729c89637 |
15 | 1d4d8a2b78 |
hex | 10e73d7e81 |
72599043713 has 12 divisors (see below), whose sum is σ = 85288112532. Its totient is φ = 61611631200.
The previous prime is 72599043707. The next prime is 72599043721. The reversal of 72599043713 is 31734099527.
It can be written as a sum of positive squares in 2 ways, for example, as 61929806449 + 10669237264 = 248857^2 + 103292^2 .
It is not a de Polignac number, because 72599043713 - 210 = 72599042689 is a prime.
It is a super-2 number, since 2×725990437132 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (72599043743) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7329770 + ... + 7339667.
It is an arithmetic number, because the mean of its divisors is an integer number (7107342711).
Almost surely, 272599043713 is an apocalyptic number.
It is an amenable number.
72599043713 is a deficient number, since it is larger than the sum of its proper divisors (12689068819).
72599043713 is a wasteful number, since it uses less digits than its factorization.
72599043713 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14669552 (or 14669545 counting only the distinct ones).
The product of its (nonzero) digits is 1428840, while the sum is 50.
The spelling of 72599043713 in words is "seventy-two billion, five hundred ninety-nine million, forty-three thousand, seven hundred thirteen".
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