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73134331141 = 96431758411
BaseRepresentation
bin100010000011100100…
…1010101010100000101
320222202212010221220011
41010013021111110011
52144234342044031
653333014310221
75166223362214
oct1040711252405
9228685127804
1073134331141
112901a472493
1212210658371
136b86902b71
14377adc907b
151d8088b6b1
hex1107255505

73134331141 has 4 divisors (see below), whose sum is σ = 73135185984. Its totient is φ = 73133476300.

The previous prime is 73134331069. The next prime is 73134331229. The reversal of 73134331141 is 14113343137.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 73134331141 - 215 = 73134298373 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (73134331241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282775 + ... + 475636.

It is an arithmetic number, because the mean of its divisors is an integer number (18283796496).

Almost surely, 273134331141 is an apocalyptic number.

It is an amenable number.

73134331141 is a deficient number, since it is larger than the sum of its proper divisors (854843).

73134331141 is an equidigital number, since it uses as much as digits as its factorization.

73134331141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 854842.

The product of its digits is 9072, while the sum is 31.

Adding to 73134331141 its reverse (14113343137), we get a palindrome (87247674278).

The spelling of 73134331141 in words is "seventy-three billion, one hundred thirty-four million, three hundred thirty-one thousand, one hundred forty-one".

Divisors: 1 96431 758411 73134331141