Base | Representation |
---|---|
bin | 100010001111011111… |
… | …0111000010011010101 |
3 | 21000210201122122021111 |
4 | 1010132332320103111 |
5 | 2201044231302203 |
6 | 53440422015021 |
7 | 5212150522114 |
oct | 1043676702325 |
9 | 230721578244 |
10 | 73534244053 |
11 | 29205188a26 |
12 | 12302577471 |
13 | 6c1b71391a |
14 | 37b8169c7b |
15 | 1da5a3426d |
hex | 111efb84d5 |
73534244053 has 4 divisors (see below), whose sum is σ = 73542144160. Its totient is φ = 73526343948.
The previous prime is 73534244041. The next prime is 73534244089. The reversal of 73534244053 is 35044243537.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 73534244053 - 213 = 73534235861 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 73534243997 and 73534244015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (73534244033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3936075 + ... + 3954712.
It is an arithmetic number, because the mean of its divisors is an integer number (18385536040).
Almost surely, 273534244053 is an apocalyptic number.
It is an amenable number.
73534244053 is a deficient number, since it is larger than the sum of its proper divisors (7900107).
73534244053 is an equidigital number, since it uses as much as digits as its factorization.
73534244053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7900106.
The product of its (nonzero) digits is 604800, while the sum is 40.
The spelling of 73534244053 in words is "seventy-three billion, five hundred thirty-four million, two hundred forty-four thousand, fifty-three".
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