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7380472516133 is a prime number
BaseRepresentation
bin110101101100110011001…
…1100010100111000100101
3222010120021211010101101212
41223121212130110320211
51431410201431004013
623410313044001205
71361135663202323
oct153314634247045
928116254111355
107380472516133
11239604a366022
129b2475390205
13416c8b440492
141b7306b92d13
15cbeb2ab66a8
hex6b666714e25

7380472516133 has 2 divisors, whose sum is σ = 7380472516134. Its totient is φ = 7380472516132.

The previous prime is 7380472516129. The next prime is 7380472516141. The reversal of 7380472516133 is 3316152740837.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7079095671649 + 301376844484 = 2660657^2 + 548978^2 .

It is a cyclic number.

It is not a de Polignac number, because 7380472516133 - 22 = 7380472516129 is a prime.

It is a super-2 number, since 2×73804725161332 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7380472516633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3690236258066 + 3690236258067.

It is an arithmetic number, because the mean of its divisors is an integer number (3690236258067).

Almost surely, 27380472516133 is an apocalyptic number.

It is an amenable number.

7380472516133 is a deficient number, since it is larger than the sum of its proper divisors (1).

7380472516133 is an equidigital number, since it uses as much as digits as its factorization.

7380472516133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 50.

The spelling of 7380472516133 in words is "seven trillion, three hundred eighty billion, four hundred seventy-two million, five hundred sixteen thousand, one hundred thirty-three".