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740391280493 is a prime number
BaseRepresentation
bin10101100011000101100…
…00100101111101101101
32121210002010211001011112
422301202300211331231
544112310131433433
61324044150401405
7104330405021534
oct12614260457555
92553063731145
10740391280493
11265aa8637547
12bb5ab660265
1354a845ca007
1427b9984731b
15143d50ce348
hexac62c25f6d

740391280493 has 2 divisors, whose sum is σ = 740391280494. Its totient is φ = 740391280492.

The previous prime is 740391280469. The next prime is 740391280501. The reversal of 740391280493 is 394082193047.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 488750597449 + 251640683044 = 699107^2 + 501638^2 .

It is a cyclic number.

It is not a de Polignac number, because 740391280493 - 26 = 740391280429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (740391280423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 370195640246 + 370195640247.

It is an arithmetic number, because the mean of its divisors is an integer number (370195640247).

Almost surely, 2740391280493 is an apocalyptic number.

It is an amenable number.

740391280493 is a deficient number, since it is larger than the sum of its proper divisors (1).

740391280493 is an equidigital number, since it uses as much as digits as its factorization.

740391280493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 50.

The spelling of 740391280493 in words is "seven hundred forty billion, three hundred ninety-one million, two hundred eighty thousand, four hundred ninety-three".